JEE Main 20198 Apr, Morning shiftMathematicsHardThree Dimensional Geometry249× since 2002The length of the perpendicular from the point (2, –1, 4) on the straight line, x+310{{x + 3} \over {10}}10x+3= y−2−7{{y - 2} \over {-7}}−7y−2 = z1{{z} \over {1}}1z is :AOption A. less than 2BOption B. greater than 4COption C. greater than 2 but less than 3DOption D. greater than 3 but less than 4CheckSkip · show solution
