JEE Main 202226 Jul, Morning shiftMathematicsMediumThree Dimensional Geometry249× since 2002The length of the perpendicular from the point (1,−2,5)(1,-2,5)(1,−2,5) on the line passing through (1,2,4)(1,2,4)(1,2,4) and parallel to the line x+y−z=0=x−2y+3z−5x+y-z=0=x-2 y+3 z-5x+y−z=0=x−2y+3z−5 is :AOption A. 212\sqrt{\frac{21}{2}}221BOption B. 92\sqrt{\frac{9}{2}}29COption C. 732\sqrt{\frac{73}{2}}273DOption D. 1CheckSkip · show solution
