JEE Main 201912 Apr, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002The length of the perpendicular drawn from the point (2, 1, 4) to the plane containing the lines r→=(i^+j^)+λ(i^+2j^−k^)\overrightarrow r = \left( {\widehat i + \widehat j} \right) + \lambda \left( {\widehat i + 2\widehat j - \widehat k} \right)r=(i+j)+λ(i+2j−k) and r→=(i^+j^)+μ(−i^+j^−2k^)\overrightarrow r = \left( {\widehat i + \widehat j} \right) + \mu \left( { - \widehat i + \widehat j - 2\widehat k} \right)r=(i+j)+μ(−i+j−2k) is :AOption A. 13{1 \over 3}31BOption B. 13{1 \over {\sqrt 3 }}31COption C. 3DOption D. 3{\sqrt 3 }3CheckSkip · show solution
