JEE Main 201910 Jan, Evening shiftMathematicsMediumCoordinate Geometry478× since 2002The length of the chord of the parabola x² === 4y having equation x – 2y+42=0\sqrt 2 y + 4\sqrt 2 = 02y+42=0 is -AOption A. 828\sqrt 282BOption B. 636\sqrt 363COption C. 323\sqrt 232DOption D. 2112\sqrt {11}211CheckSkip · show solution
