Atoms and Nuclei: JEE Main 2021 Physics question

JEE Main 2021 · 27 Jul, Evening shift · Q56

JEE Main 202127 Jul, Evening shiftPhysicsMediumAtoms and Nuclei183× since 2002

The K_

\alpha

X-ray of molybdenum has wavelength 0.071 nm. If the energy of a molybdenum atoms with a K electron knocked out is 27.5 keV, the energy of this atom when an L electron is knocked out will be __________ keV. (Round off to the nearest integer) [h = 4.14

\times

10^

-

15 eVs, c = 3

\times

10⁸ ms^

-

Your answerType your answer. Integers and decimals are accepted.

More on Atoms and Nuclei

Practise this topic

JEE Main 2021 Atoms and Nuclei Question with Answer (27 Jul Evening shift, Q56) | JEE Arc