JEE Main 202117 Mar, Morning shiftMathematicsEasySets, Relations and Functions168× since 2002The inverse of y=5logxy = {5^{\log x}}y=5logx is :AOption A. x=5logyx = {5^{\log y}}x=5logyBOption B. x=y1log5x = {y^{{1 \over {\log 5}}}}x=ylog51COption C. x=51logyx = {5^{{1 \over {\log y}}}}x=5logy1DOption D. x=ylog5x = {y^{\log 5}}x=ylog5CheckSkip · show solution