JEE Main 201911 Jan, Evening shiftMathematicsEasyIntegral Calculus369× since 2002The integral ∫π/6π/4dxsin2x(tan5x+cot5x)\int\limits_{\pi /6}^{\pi /4} {{{dx} \over {\sin 2x\left( {{{\tan }^5}x + {{\cot }^5}x} \right)}}}π/6∫π/4sin2x(tan5x+cot5x)dx equals :AOption A. π40{\pi \over {40}}40πBOption B. 120tan−1(193){1 \over {20}}{\tan ^{ - 1}}\left( {{1 \over {9\sqrt 3 }}} \right)201tan−1(931)COption C. 110(π4−tan−1(193)){1 \over {10}}\left( {{\pi \over 4} - {{\tan }^{ - 1}}\left( {{1 \over {9\sqrt 3 }}} \right)} \right)101(4π−tan−1(931))DOption D. 15(π4−tan−1(133)){1 \over 5}\left( {{\pi \over 4}{{-\tan }^{ - 1}}\left( {{1 \over {3\sqrt 3 }}} \right)} \right)51(4π−tan−1(331))CheckSkip · show solution
