JEE Main 202227 Jun, Evening shiftMathematicsMediumIntegral Calculus369× since 2002The integral ∫0117[1x]dx\int\limits_0^1 {{1 \over {{7^{\left[ {{1 \over x}} \right]}}}}dx}0∫17[x1]1dx, where [ . ] denotes the greatest integer function, is equal toAOption A. 1+6loge(67)1 + 6{\log _e}\left( {{6 \over 7}} \right)1+6loge(76)BOption B. 1−6loge(67)1 - 6{\log _e}\left( {{6 \over 7}} \right)1−6loge(76)COption C. loge(76){\log _e}\left( {{7 \over 6}} \right)loge(67)DOption D. 1−7loge(67)1 - 7{\log _e}\left( {{6 \over 7}} \right)1−7loge(76)CheckSkip · show solution
