The integral ∫ dx/((x + 4)^(8/7)(x - 3)^(6/7)) is equal to: (where C is a constant of integration)

(B) ((x - 3)/(x + 4))^(1/7) + C

(A) 1/2((x - 3)/(x + 4))^(3/7) + C

(C) - 1/13((x - 3)/(x + 4))^(13/7) + C

(D) - ((x - 3)/(x + 4))^(-1/7) + C

Integral Calculus: JEE Main 2020 Mathematics question

JEE Main 2020 · 9 Jan, Morning shift · Q4025

JEE Main 20209 Jan, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

The integral

\int {{{dx} \over {{{(x + 4)}^{{8 \over 7}}}{{(x - 3)}^{{6 \over 7}}}}}}

is equal to : (where C is a constant of integration)

JEE Main 2020 · 9 Jan, Morning shift · Q4025

JEE Main 20209 Jan, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

The integral

\int {{{dx} \over {{{(x + 4)}^{{8 \over 7}}}{{(x - 3)}^{{6 \over 7}}}}}}

is equal to : (where C is a constant of integration)