JEE Main 202118 Mar, Morning shiftMathematicsEasyIntegral Calculus369× since 2002The integral ∫(2x−1)cos(2x−1)2+54x2−4x+6dx\int {{{(2x - 1)\cos \sqrt {{{(2x - 1)}^2} + 5} } \over {\sqrt {4{x^2} - 4x + 6} }}} dx∫4x2−4x+6(2x−1)cos(2x−1)2+5dx is equal to (where c is a constant of integration)AOption A. 12sin(2x−1)2+5+c{1 \over 2}\sin \sqrt {{{(2x - 1)}^2} + 5} + c21sin(2x−1)2+5+cBOption B. 12cos(2x+1)2+5+c{1 \over 2}\cos \sqrt {{{(2x + 1)}^2} + 5} + c21cos(2x+1)2+5+cCOption C. 12cos(2x−1)2+5+c{1 \over 2}\cos \sqrt {{{(2x - 1)}^2} + 5} + c21cos(2x−1)2+5+cDOption D. 12sin(2x+1)2+5+c{1 \over 2}\sin \sqrt {{{(2x + 1)}^2} + 5} + c21sin(2x+1)2+5+cCheckSkip · show solution
