JEE Main 202131 Aug, Morning shiftMathematicsEasyIntegral Calculus369× since 2002The integral ∫1\root4\of(x−1)3(x+2)5 dx\int {{1 \over {\root 4 \of {{{(x - 1)}^3}{{(x + 2)}^5}} }}} \,dx∫\root4\of(x−1)3(x+2)51dx is equal to : (where C is a constant of integration)AOption A. 34(x+2x−1)14+C{3 \over 4}{\left( {{{x + 2} \over {x - 1}}} \right)^{{1 \over 4}}} + C43(x−1x+2)41+CBOption B. 34(x+2x−1)54+C{3 \over 4}{\left( {{{x + 2} \over {x - 1}}} \right)^{{5 \over 4}}} + C43(x−1x+2)45+CCOption C. 43(x−1x+2)14+C{4 \over 3}{\left( {{{x - 1} \over {x + 2}}} \right)^{{1 \over 4}}} + C34(x+2x−1)41+CDOption D. 43(x−1x+2)54+C{4 \over 3}{\left( {{{x - 1} \over {x + 2}}} \right)^{{5 \over 4}}} + C34(x+2x−1)45+CCheckSkip · show solution
