The hydrogen electrode is dipped in a solution of pH=3 at 25^(°) C. The potential of the electrode will be _ _ _ _ _ × 10⁻² ~V. ((2.303 RT)/F=0.059 ~V)

Redox Reactions and Electrochemistry: JEE Main 2024 Chemistry question

JEE Main 2024 · 27 Jan, Evening shift · Q14

JEE Main 202427 Jan, Evening shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

The hydrogen electrode is dipped in a solution of

\mathrm{pH}=3

25^{\circ} \mathrm{C}

. The potential of the electrode will be _________

\times 10^{-2} \mathrm{~V}

\left(\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V}\right)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2024 · 27 Jan, Evening shift · Q14

JEE Main 202427 Jan, Evening shiftChemistryMediumRedox Reactions and Electrochemistry138× since 2002

The hydrogen electrode is dipped in a solution of

\mathrm{pH}=3

25^{\circ} \mathrm{C}

. The potential of the electrode will be _________

\times 10^{-2} \mathrm{~V}

\left(\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059 \mathrm{~V}\right)

Your answerType your answer. Integers and decimals are accepted.