JEE Main 20204 Sep, Evening shiftMathematicsHardLimit, Continuity and Differentiability420× since 2002The function f(x)={π4+tan−1x,∣x∣≤112(∣x∣−1),∣x∣>1f(x) = \left\{ {\matrix{ {{\pi \over 4} + {{\tan }^{ - 1}}x,} & {\left| x \right| \le 1} \cr {{1 \over 2}\left( {\left| x \right| - 1} \right),} & {\left| x \right| > 1} \cr } } \right.f(x)={4π+tan−1x,21(∣x∣−1),∣x∣≤1∣x∣>1 is :AOption A. continuous on R–{–1} and differentiable on R–{–1, 1}BOption B. both continuous and differentiable on R–{1}COption C. both continuous and differentiable on R–{–1}DOption D. continuous on R–{1} and differentiable on R–{–1, 1}CheckSkip · show solution