JEE Main 202429 Jan, Evening shiftMathematicsEasyLimit, Continuity and Differentiability420× since 2002The function f(x)=xx2−6x−16,x∈R−{−2,8}f(x)=\frac{x}{x^2-6 x-16}, x \in \mathbb{R}-\{-2,8\}f(x)=x2−6x−16x,x∈R−{−2,8}AOption A. decreases in (−∞,−2)∪(−2,8)∪(8,∞)(-\infty,-2) \cup(-2,8) \cup(8, \infty)(−∞,−2)∪(−2,8)∪(8,∞)BOption B. increases in (−∞,−2)∪(−2,8)∪(8,∞)(-\infty,-2) \cup(-2,8) \cup(8, \infty)(−∞,−2)∪(−2,8)∪(8,∞)COption C. decreases in (−2,8)(-2,8)(−2,8) and increases in (−∞,−2)∪(8,∞)(-\infty,-2) \cup(8, \infty)(−∞,−2)∪(8,∞)DOption D. decreases in (−∞,−2)(-\infty,-2)(−∞,−2) and increases in (8,∞)(8, \infty)(8,∞)CheckSkip · show solution
