JEE Main 202124 Feb, Morning shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002The function f(x) = 4x3−3x26−2sinx+(2x−1)cosx{{4{x^3} - 3{x^2}} \over 6} - 2\sin x + \left( {2x - 1} \right)\cos x64x3−3x2−2sinx+(2x−1)cosx :AOption A. increases in (−∞,12]\left( { - \infty ,{1 \over 2}} \right](−∞,21]BOption B. decreases in (−∞,12]\left( { - \infty ,{1 \over 2}} \right](−∞,21]COption C. increases in [12,∞)\left[ {{1 \over 2},\infty } \right)[21,∞)DOption D. decreases in [12,∞)\left[ {{1 \over 2},\infty } \right)[21,∞)CheckSkip · show solution
