JEE Main 202431 Jan, Evening shiftChemistryEasyAtomic Structure113× since 2002The four quantum numbers for the electron in the outer most orbital of potassium (atomic no. 19) areAOption A. n=3,l=0, m=1, s=+12\mathrm{n}=3, l=0, \mathrm{~m}=1, \mathrm{~s}=+\frac{1}{2}n=3,l=0, m=1, s=+21BOption B. n=4,l=0, m=0,s=+12\mathrm{n}=4, l=0, \mathrm{~m}=0, s=+\frac{1}{2}n=4,l=0, m=0,s=+21COption C. n=2,l=0, m=0,s=+12\mathrm{n}=2, l=0, \mathrm{~m}=0, s=+\frac{1}{2}n=2,l=0, m=0,s=+21DOption D. n=4,l=2, m=−1,s=+12\mathrm{n}=4, l=2, \mathrm{~m}=-1, s=+\frac{1}{2}n=4,l=2, m=−1,s=+21CheckSkip · show solution
