The equilibrium constant for the reversible reaction 2A(g) 2B(g) + C(g) is K₁ 3/2 A(g) 3/2 B(g) + 3/4 C(g) is K₂. K₁ and K₂ are related as:

Equilibrium: JEE Main 2022 Chemistry question

JEE Main 2022 · 30 Jun, Morning shift · Q421

JEE Main 202230 Jun, Morning shiftChemistryEasyEquilibrium123× since 2002

The equilibrium constant for the reversible reaction 2A(g)

\rightleftharpoons

2B(g) + C(g) is K₁

{3 \over 2}

A(g)

\rightleftharpoons

{3 \over 2}

B(g) +

{3 \over 4}

C(g) is K₂. K₁ and K₂ are related as :