JEE Main 20244 Apr, Evening shiftChemistryMediumEquilibrium123× since 2002The equilibrium constant for the reaction SO3( g)⇌SO2( g)+12O2( g)\mathrm{SO}_3(\mathrm{~g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})SO3( g)⇌SO2( g)+21O2( g) is Kc=4.9×10−2\mathrm{K}_{\mathrm{c}}=4.9 \times 10^{-2}Kc=4.9×10−2. The value of Kc\mathrm{K}_{\mathrm{c}}Kc for the reaction given below is 2SO2( g)+O2( g)⇌2SO3( g)2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})2SO2( g)+O2( g)⇌2SO3( g) is :AOption A. 49BOption B. 416COption C. 41.6DOption D. 4.9CheckSkip · show solution
