JEE Main 2010Annual, Paper 1MathematicsEasyLimit, Continuity and Differentiability420× since 2002The equation of the tangent to the curve y=x+4x2y = x + {4 \over {{x^2}}}y=x+x24, that is parallel to the xxx-axis, isAOption A. y=1y=1y=1BOption B. y=2y=2y=2COption C. y=3y=3y=3DOption D. y=0y=0y=0CheckSkip · show solution
