JEE Main 2004Annual, Paper 1MathematicsMediumCoordinate Geometry478× since 2002The equation of the straight line passing through the point (4,3)(4, 3)(4,3) and making intercepts on the co-ordinate axes whose sum is −1-1−1 is :AOption A. x2−y3=1{x \over 2} - {y \over 3} = 12x−3y=1 and x−2+y1=1{x \over -2} +{y \over 1} = 1−2x+1y=1BOption B. x2−y3=−1{x \over 2} - {y \over 3} = -12x−3y=−1 and x−2+y1=−1{x \over -2} +{y \over 1} = -1−2x+1y=−1COption C. x2+y3=1{x \over 2} + {y \over 3} = 12x+3y=1 and x2+y1=1{x \over 2} +{y \over 1} = 12x+1y=1DOption D. x2+y3=−1{x \over 2} + {y \over 3} = -12x+3y=−1 and x−2+y1=−1{x \over -2} +{y \over 1} = -1−2x+1y=−1CheckSkip · show solution
