JEE Main 2015Session, Shift 1MathematicsMediumThree Dimensional Geometry249× since 2002The equation of the plane containing the line 2x−5y+z=3;x+y+4z=5,2x-5y+z=3; x+y+4z=5,2x−5y+z=3;x+y+4z=5, and parallel to the plane, x+3y+6z=1,x+3y+6z=1,x+3y+6z=1, is :AOption A. x+3y+6z=7x+3y+6z=7x+3y+6z=7BOption B. 2x+6y+12z=−132x+6y+12z=-132x+6y+12z=−13COption C. 2x+6y+12z=132x+6y+12z=132x+6y+12z=13DOption D. x+3y+6z=−7x+3y+6z=-7x+3y+6z=−7CheckSkip · show solution
