JEE Main 20202 Sep, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002The equation of the normal to the curve y = (1+x)2y + cos ²(sin^–1x) at x = 0 is :AOption A. y = 4x + 2BOption B. x + 4y = 8COption C. y + 4x = 2DOption D. 2y + x = 4CheckSkip · show solution
