JEE Main 2013Session, Shift 1MathematicsMediumCoordinate Geometry478× since 2002The equation of the circle passing through the foci of the ellipse x216+y29=1{{{x^2}} \over {16}} + {{{y^2}} \over 9} = 116x2+9y2=1, and having centre at (0,3)(0,3)(0,3) is :AOption A. x2+y2−6y−7=0{x^2} + {y^2} - 6y - 7 = 0x2+y2−6y−7=0BOption B. x2+y2−6y+7=0{x^2} + {y^2} - 6y + 7 = 0x2+y2−6y+7=0COption C. x2+y2−6y−5=0{x^2} + {y^2} - 6y - 5 = 0x2+y2−6y−5=0DOption D. x2+y2−6y+5=0{x^2} + {y^2} - 6y + 5 = 0x2+y2−6y+5=0CheckSkip · show solution
