The equation of current in a purely inductive circuit is 5 sin (49 π t-30^(°)). If the inductance is 30 mH then the equation for the voltage across the inductor, will be: \. Let.π=22/7

Electromagnetic Induction and Alternating Currents: JEE Main 2022 Physics question

JEE Main 2022 · 28 Jul, Morning shift · Q5911

JEE Main 202228 Jul, Morning shiftPhysicsMediumElectromagnetic Induction and Alternating Currents149× since 2002

The equation of current in a purely inductive circuit is

5 \sin \left(49\, \pi t-30^{\circ}\right)

. If the inductance is

30 \,\mathrm{mH}

then the equation for the voltage across the inductor, will be :

\left\{\right.

Let

\left.\pi=\frac{22}{7}\right\}

JEE Main 2022 · 28 Jul, Morning shift · Q5911

JEE Main 202228 Jul, Morning shiftPhysicsMediumElectromagnetic Induction and Alternating Currents149× since 2002

The equation of current in a purely inductive circuit is

5 \sin \left(49\, \pi t-30^{\circ}\right)

. If the inductance is

30 \,\mathrm{mH}

then the equation for the voltage across the inductor, will be :

\left\{\right.

Let

\left.\pi=\frac{22}{7}\right\}