JEE Main 2010Annual, Paper 1PhysicsMediumOscillations and Waves185× since 2002The equation of a wave on a string of linear mass density 0.04 kg m−10.04\,\,kg\,{m^{ - 1}}0.04kgm−1 is given by y=0.02(m) sin[2π(t0.04(s)−x0.50(m))].y = 0.02\left( m \right)\,\sin \left[ {2\pi \left( {{t \over {0.04\left( s \right)}} - {x \over {0.50\left( m \right)}}} \right)} \right].y=0.02(m)sin[2π(0.04(s)t−0.50(m)x)]. The tension in the string isAOption A. 4.0N4.0N4.0NBOption B. 12.512.512.5 NNNCOption C. 0.50.50.5 NNNDOption D. 6.256.256.25 NNNCheckSkip · show solution
