JEE Main 201912 Jan, Evening shiftMathematicsEasyCoordinate Geometry478× since 2002The equation of a tangent to the parabola, x² = 8y, which makes an angle θ\thetaθ with the positive directions of x-axis, is :AOption A. x = y cot θ\thetaθ – 2 tan θ\thetaθBOption B. y = x tan θ\thetaθ + 2 cot θ\thetaθCOption C. x = y cot θ\thetaθ + 2 tan θ\thetaθDOption D. y = x tan θ\thetaθ – 2 cot θ\thetaθCheckSkip · show solution
