JEE Main 2002Annual, Paper 1MathematicsMediumCoordinate Geometry478× since 2002The equation of a circle with origin as a center and passing through an equilateral triangle whose median is of length 333aaa is :AOption A. x2 + y2=9a2{x^2}\, + \,{y^2} = 9{a^2}x2+y2=9a2BOption B. x2 + y2=16a2{x^2}\, + \,{y^2} = 16{a^2}x2+y2=16a2COption C. x2 + y2=4a2{x^2}\, + \,{y^2} = 4{a^2}x2+y2=4a2DOption D. x2 + y2=a2{x^2}\, + \,{y^2} = {a^2}x2+y2=a2CheckSkip · show solution
