The equation λ=1.227/x ~nm can be used to find the de-Brogli wavelength of an electron. In this equation x stands for: Where m= mass of electron P= momentum of electron K= Kinetic energy of electron V= Accelerating potential in volts for electron

Dual Nature of Matter and Radiation: JEE Main 2022 Physics question

JEE Main 2022 · 28 Jul, Morning shift · Q6576

JEE Main 202228 Jul, Morning shiftPhysicsMediumDual Nature of Matter and Radiation146× since 2002

The equation

\lambda=\frac{1.227}{x} \mathrm{~nm}

can be used to find the de-Brogli wavelength of an electron. In this equation

x

stands for : Where

\mathrm{m}=

mass of electron

\mathrm{P}=

momentum of electron

\mathrm{K}=

Kinetic energy of electron

\mathrm{V}=

Accelerating potential in volts for electron

JEE Main 2022 Dual Nature of Matter and Radiation Question with Solution (28 Jul Morning shift, Q6576) | JEE Arc