The energy released in the fusion of 2 ~kg of hydrogen deep in the sun is E H and the energy released in the fission of 2 ~kg of ²³⁵ U is E U. The ratio E H /E U is approximately: (Consider the fusion reaction as 4₁¹H+2 e⁻ → ₂⁴ He+2 v+6 γ+26.7 ~MeV, energy released in the fission reaction of ²³⁵ U is 200 ~MeV per fission nucleus and N A = 6.023 × 10²³)

Atoms and Nuclei: JEE Main 2024 Physics question

JEE Main 2024 · 9 Apr, Evening shift · Q6062

JEE Main 20249 Apr, Evening shiftPhysicsHardAtoms and Nuclei183× since 2002

The energy released in the fusion of

2 \mathrm{~kg}

of hydrogen deep in the sun is

E_H

and the energy released in the fission of

2 \mathrm{~kg}

{ }^{235} \mathrm{U}

E_U

. The ratio

\frac{E_H}{E_U}

is approximately: (Consider the fusion reaction as

4_1^1H+2 \mathrm{e}^{-} \rightarrow{ }_2^4 \mathrm{He}+2 v+6 \gamma+26.7 \mathrm{~MeV}

, energy released in the fission reaction of

{ }^{235} \mathrm{U}

200 \mathrm{~MeV}

per fission nucleus and

\mathrm{N}_{\mathrm{A}}= 6.023 \times 10^{23})

JEE Main 2024 Atoms and Nuclei Question with Solution (9 Apr Evening shift, Q6062) | JEE Arc