The domain of the function f(x) = (sin ⁻¹(x - 3))/(√(9 - x²))

Sets, Relations and Functions: JEE Main 2004 Mathematics question

JEE Main 2004 · Annual, Paper 1 · Q3839

JEE Main 2004Annual, Paper 1MathematicsEasySets, Relations and Functions168× since 2002

The domain of the function

f\left( x \right) = {{{{\sin }^{ - 1}}\left( {x - 3} \right)} \over {\sqrt {9 - {x^2}} }}

JEE Main 2004 · Annual, Paper 1 · Q3839

JEE Main 2004Annual, Paper 1MathematicsEasySets, Relations and Functions168× since 2002

The domain of the function

f\left( x \right) = {{{{\sin }^{ - 1}}\left( {x - 3} \right)} \over {\sqrt {9 - {x^2}} }}