JEE Main 202329 Jan, Morning shiftMathematicsEasySets, Relations and Functions168× since 2002The domain of f(x)=log(x+1)(x−2)e2logex−(2x+3),x∈Rf(x) = {{{{\log }_{(x + 1)}}(x - 2)} \over {{e^{2{{\log }_e}x}} - (2x + 3)}},x \in \mathbb{R}f(x)=e2logex−(2x+3)log(x+1)(x−2),x∈R isAOption A. (−1,∞)−{3}( - 1,\infty ) - \{ 3\}(−1,∞)−{3}BOption B. R−{−1,3)\mathbb{R} - \{ - 1,3)R−{−1,3)COption C. (2,∞)−{3}(2,\infty ) - \{ 3\}(2,∞)−{3}DOption D. R−{3}\mathbb{R} - \{ 3\}R−{3}CheckSkip · show solution
