JEE Main 202313 Apr, Evening shiftPhysicsMediumKinematics177× since 2002The distance travelled by an object in time ttt is given by s=(2.5)t2s=(2.5) t^{2}s=(2.5)t2. The instantaneous speed of the object at t=5 s\mathrm{t}=5 \mathrm{~s}t=5 s will be:AOption A. 5 ms−15 \mathrm{~ms}^{-1}5 ms−1BOption B. 12.5 ms−112.5 \mathrm{~ms}^{-1}12.5 ms−1COption C. 62.5 ms−162.5 \mathrm{~ms}^{-1}62.5 ms−1DOption D. 25 ms−125 \mathrm{~ms}^{-1}25 ms−1CheckSkip · show solution
