JEE Main 202325 Jan, Evening shiftPhysicsEasyKinematics177× since 2002The distance travelled by a particle is related to time t as x=4t2x=4\mathrm{t}^2x=4t2. The velocity of the particle at t=5s is :-AOption A. 25 ms−1\mathrm{25~ms^{-1}}25 ms−1BOption B. 20 ms−1\mathrm{20~ms^{-1}}20 ms−1COption C. 8 ms−1\mathrm{8~ms^{-1}}8 ms−1DOption D. 40 ms−1\mathrm{40~ms^{-1}}40 ms−1CheckSkip · show solution
