JEE Main 2016Session, Shift 1MathematicsMediumThree Dimensional Geometry249× since 2002The distance of the point (1,−5,9)(1,-5,9)(1,−5,9) from the plane x−y+z=5x-y+z=5x−y+z=5 measured along the line x=y=zx=y=zx=y=z is :AOption A. 103{{10} \over {\sqrt 3 }}310BOption B. 203{20 \over 3}320COption C. 3103\sqrt {10}310DOption D. 10310\sqrt {3}103CheckSkip · show solution
