Three Dimensional Geometry: JEE Main 2017 Mathematics question

JEE Main 2017 · Session, Shift 1 · Q2400

JEE Main 2017Session, Shift 1MathematicsMediumThree Dimensional Geometry249× since 2002

The distance of the point (1, 3, – 7) from the plane passing through the point (1, –1, – 1), having normal perpendicular to both the lines

{{x - 1} \over 1} = {{y + 2} \over { - 2}} = {{z - 4} \over 3}

and

{{x - 2} \over 2} = {{y + 1} \over { - 1}} = {{z + 7} \over { - 1}}

is :

JEE Main 2017 · Session, Shift 1 · Q2400

JEE Main 2017Session, Shift 1MathematicsMediumThree Dimensional Geometry249× since 2002

The distance of the point (1, 3, – 7) from the plane passing through the point (1, –1, – 1), having normal perpendicular to both the lines

{{x - 1} \over 1} = {{y + 2} \over { - 2}} = {{z - 4} \over 3}

and

{{x - 2} \over 2} = {{y + 1} \over { - 1}} = {{z + 7} \over { - 1}}

is :

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