JEE Main 20204 Sep, Evening shiftMathematicsMediumThree Dimensional Geometry249× since 2002The distance of the point (1, –2, 3) from the plane x – y + z = 5 measured parallel to the line x2=y3=z−6{x \over 2} = {y \over 3} = {z \over { - 6}}2x=3y=−6z is :AOption A. 7BOption B. 1COption C. 17{1 \over 7}71DOption D. 75{7 \over 5}57CheckSkip · show solution