JEE Main 20211 Sep, Evening shiftMathematicsEasyThree Dimensional Geometry249× since 2002The distance of line 3y−2z−1=0=3x−z+43y - 2z - 1 = 0 = 3x - z + 43y−2z−1=0=3x−z+4 from the point (2, −-−1, 6) is :AOption A. 26\sqrt {26}26BOption B. 252\sqrt 525COption C. 262\sqrt 626DOption D. 424\sqrt 242CheckSkip · show solution
