JEE Main 2003Annual, Paper 1PhysicsEasyOscillations and Waves185× since 2002The displacement of particle varies according to the relation x=4x=4x=4(cos πt+sin πt).\left( {\cos \,\pi t + \sin \,\pi t} \right).(cosπt+sinπt). The amplitude of the particle isAOption A. −4-4−4BOption B. 444COption C. 424\sqrt 242DOption D. 888CheckSkip · show solution