JEE Main 20207 Jan, Evening shiftPhysicsEasyUnits and Measurements122× since 2002The dimension of B22μ0{{{B^2}} \over {2{\mu _0}}}2μ0B2, where B is magnetic field and μ0{{\mu _0}}μ0 is the magnetic permeability of vacuum, is :AOption A. ML²T^–2BOption B. MLT^–2COption C. ML⁻¹T^–2DOption D. ML²T^–1CheckSkip · show solution