JEE Main 2007Annual, Paper 1MathematicsMediumDifferential Equations163× since 2002The differential equation of all circles passing through the origin and having their centres on the xxx-axis is :AOption A. y2=x2+2xydydx{y^2} = {x^2} + 2xy{{dy} \over {dx}}y2=x2+2xydxdyBOption B. y2=x2−2xydydx{y^2} = {x^2} - 2xy{{dy} \over {dx}}y2=x2−2xydxdyCOption C. x2=y2+xydydx{x^2} = {y^2} + xy{{dy} \over {dx}}x2=y2+xydxdyDOption D. x2=y2+3xydydx{x^2} = {y^2} + 3xy{{dy} \over {dx}}x2=y2+3xydxdyCheckSkip · show solution
