JEE Main 20205 Sep, Evening shiftMathematicsMediumLimit, Continuity and Differentiability420× since 2002The derivative of tan−1(1+x2−1x){\tan ^{ - 1}}\left( {{{\sqrt {1 + {x^2}} - 1} \over x}} \right)tan−1(x1+x2−1) with respect to tan−1(2x1−x21−2x2){\tan ^{ - 1}}\left( {{{2x\sqrt {1 - {x^2}} } \over {1 - 2{x^2}}}} \right)tan−1(1−2x22x1−x2) at x = 12{1 \over 2}21 is :AOption A. 233{{2\sqrt 3 } \over 3}323BOption B. 235{{2\sqrt 3 } \over 5}523COption C. 310{{\sqrt 3 } \over {10}}103DOption D. 312{{\sqrt 3 } \over {12}}123CheckSkip · show solution
