JEE Main 202331 Jan, Morning shiftPhysicsEasyThermodynamics163× since 2002The correct relation between γ=cpcv\gamma = {{{c_p}} \over {{c_v}}}γ=cvcp and temperature T is :AOption A. γ∝T\gamma \propto Tγ∝TBOption B. γ∝1T\gamma \propto {1 \over {\sqrt T }}γ∝T1COption C. γ∝1T\gamma \propto {1 \over T}γ∝T1DOption D. γ∝T∘\gamma \propto T^\circγ∝T∘CheckSkip · show solution
