JEE Main 202313 Apr, Evening shiftMathematicsEasyBinomial Theorem and Its Simple Applications131× since 2002The coefficient of x5x^{5}x5 in the expansion of (2x3−13x2)5\left(2 x^{3}-\frac{1}{3 x^{2}}\right)^{5}(2x3−3x21)5 is :AOption A. 263\frac{26}{3}326BOption B. 809\frac{80}{9}980COption C. 9DOption D. 8CheckSkip · show solution