JEE Main 20244 Apr, Morning shiftPhysicsHardKinematics177× since 2002The co-ordinates of a particle moving in xxx-yyy plane are given by : x=2+4t,y=3t+8t2x=2+4 \mathrm{t}, y=3 \mathrm{t}+8 \mathrm{t}^2x=2+4t,y=3t+8t2. The motion of the particle is :AOption A. uniform motion along a straight line.BOption B. non-uniformly accelerated.COption C. uniformly accelerated having motion along a straight line.DOption D. uniformly accelerated having motion along a parabolic path.CheckSkip · show solution
