JEE Main 2016Session, Shift 1MathematicsMediumCoordinate Geometry478× since 2002The centres of those circles which touch the circle, x2+y2−8x−8y−4=0{x^2} + {y^2} - 8x - 8y - 4 = 0x2+y2−8x−8y−4=0, externally and also touch the xxx-axis, lie on :AOption A. a circleBOption B. an ellipse which is not a circleCOption C. a hyperbolaDOption D. a parabolaCheckSkip · show solution
