JEE Main 2002Annual, Paper 1MathematicsMediumCoordinate Geometry478× since 2002The centre of the circle passing through (0, 0) and (1, 0) and touching the circle x2 + y2=9{x^2}\, + \,{y^2} = 9x2+y2=9 is :AOption A. (12, 12)\left( {{1 \over 2},\,{1 \over 2}} \right)(21,21)BOption B. (12, − 2)\left( {{1 \over 2},\, - \,\sqrt 2 } \right)(21,−2)COption C. (32, 12)\left( {{3 \over 2},\,{1 \over 2}} \right)(23,21)DOption D. (12, 32)\left( {{1 \over 2},\,{3 \over 2}} \right)(21,23)CheckSkip · show solution
