JEE Main 202431 Jan, Evening shiftMathematicsMediumIntegral Calculus369× since 2002The area of the region enclosed by the parabolas y=4x−x2y=4 x-x^2y=4x−x2 and 3y=(x−4)23 y=(x-4)^23y=(x−4)2 is equal to :AOption A. 329\frac{32}{9}932BOption B. 143\frac{14}{3}314COption C. 4DOption D. 6CheckSkip · show solution