JEE Main 2008Annual, Paper 1MathematicsMediumIntegral Calculus369× since 2002The area of the plane region bounded by the curves x+2y2=0x + 2{y^2} = 0x+2y2=0 and x+3y2=1\,x + 3{y^2} = 1x+3y2=1 is equal to :AOption A. 53{5 \over 3}35BOption B. 13{1 \over 3}31COption C. 23{2 \over 3}32DOption D. 43{4 \over 3}34CheckSkip · show solution