JEE Main 202124 Feb, Morning shiftMathematicsHardIntegral Calculus369× since 2002The area (in sq. units) of the part of the circle x² + y² = 36, which is outside the parabola y² = 9x, is :AOption A. 12π−3312\pi - 3\sqrt 312π−33BOption B. 24π+3324\pi + 3\sqrt 324π+33COption C. 24π−3324\pi - 3\sqrt 324π−33DOption D. 12π+3312\pi + 3\sqrt 312π+33CheckSkip · show solution
