Integral Calculus: JEE Main 2019 Mathematics question

JEE Main 2019 · 9 Jan, Morning shift · Q2820

JEE Main 20199 Jan, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

The area (in sq. units) bounded by the parabolae y = x² – 1, the tangent at the point (2, 3) to it and the y-axis is :

JEE Main 2019 · 9 Jan, Morning shift · Q2820

JEE Main 20199 Jan, Morning shiftMathematicsMediumIntegral Calculus369× since 2002

The area (in sq. units) bounded by the parabolae y = x² – 1, the tangent at the point (2, 3) to it and the y-axis is :

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